World number two Daniil Medvedev was eliminated from the Indian Wells Tennis Championships in the fourth round on Wednesday after losing to Bulgarian Grigor Dimitrov 4-6, 6-4, 6-3.
Medvedev broke Dimitrov’s serve in the opening match and finished the first set with a near-perfect performance, as he lost his first serve only four times, hit three aces to serve and committed only five unforced errors.
The Russian, who won his first grand slam title at the US Open last month, led by two breaks in the second set and looked on his way to an easy victory.
But Dimitrov rose up and won five games in a row, tilting the balance in his favor with Medvedev’s decline, as he won the second set by breaking his opponent’s serve before winning three consecutive games in the opening of the third set.
After trailing 15-40 when Dimitrov was leading 4-1, Medvedev missed his first serve to get angry and smash his racket and then committed a double fault to lead the Bulgarian 5-1.
The Russian responded by breaking the serve and then holding his serve, but the world number 28 completed his revolt before raising his hand to celebrate his victory.
Medvedev, who won his fourth Masters title in Toronto this year, told reporters that he struggled with ball control, especially on his first serve, and that he was tired as the momentum shifted in Dimitrov’s favor.
“I don’t remember losing three serves or even four at all, I think on the hard courts. It shows how slow the courts are here and the atmosphere is like a clay court, I am not satisfied with what happened because losing four games to my serve is not acceptable.”
Dimitrov, who won his second victory over Medvedev, plays eighth seed Hubert Hurkacz in the quarter-finals.